Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.6 Exercises - Page 155: 36

Answer

$$\frac{dp}{dt} = -1.3\frac{p}{V}\frac{dV}{dt}$$

Work Step by Step

Step-1: The following equation has been given to us, $$pV^{1.3}=k$$, where $k$ is a constant. Differentiate the above equation with respect to $t$, $$V^{1.3}\frac{dp}{dt}+ p(1.3V^{0.3})\frac{dV}{dt}=0$$ Step-2: Isolate $\frac{dp}{dt}$, $$\frac{dp}{dt} = -1.3\frac{p}{V}\frac{dV}{dt}$$
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