Answer
$\frac{1}{3}$
Work Step by Step
$y^3-x^2=4$
$\frac{d}{dx}[y^3-x^2]=\frac{d}{dx}[4]$
$3y^2\frac{dy}{dx}-2x=0$
$\frac{dy}{dx}=\frac{2x}{3y^2}$
$(2,2)$
$\frac{2x}{3y^2}=\frac{2(2)}{3(2)^2}=\frac{4}{12}=\frac{1}{3}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.5 Exercises - Page 145: 22
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