Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.5 Exercises - Page 145: 11

Answer

$\dfrac{dy}{dx}=\dfrac{\cos{x}}{4\sin{2y}}.$

Work Step by Step

$\dfrac{d}{dx}(\sin{x})+2\dfrac{d}{dx}(\cos{2y})=\dfrac{d}{dx}(1)\rightarrow$ $\cos{x}+\dfrac{dy}{dx}(-4\sin{2y})=0\rightarrow$ $\dfrac{dy}{dx}=\dfrac{\cos{x}}{4\sin{2y}}.$
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