Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.4 Exercises - Page 137: 101

Answer

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Work Step by Step

g'(x) = f'(x)(1) All the values of g'(x) are equal to those of f'(x) h'(x) = 2f'(x)(1) h'(-2) = 2(f'(-2)) = 2(4) = 8 h'(-1) = 2(f'(-1)) = 2($\dfrac{2}{3}$) = $\dfrac{4}{3}$ h'(0) = 2(f'(0)) = 2(-$\dfrac{1}{3}$) = -$\dfrac{2}{3}$ h'(1) = 2(f'(1)) - 2(-1) - -2 h'(2) = 2(f'(2)) = 2(-2) = -4 h'(3) = 2(f'(3)) = 2(-4) = -8 r'(x) = f'(-3x)(-3) = -3(f'(-3x)) r'(-2) = -3(f'(-3(-2))) = -3(f'(6)) = Not possible since f'(6) has not been given. r'(-1) = -3(f'(-3(-1))) = -3(f'(3)) = -3(-4) = 12 r'(0) = -3(f'(-3(0))) = -3(f'(0)) = -3(-$\dfrac{1}{3}$) = 1 r'(1) = -3(f'(-3(1))) = -3(f'(-3)) = Not possible since f'(-3) has not been given. r'(2) = -3(f'(-3(2))) = -3(f'(-6)) = Not possible since f'(-6) has not been given. r'(3) = -3(f'(-3(3))) = -3(f'(-9)) = Not possible since f'(-9) has not been given. s'(x) = f'(x + 2)(1) s'(-2) = f'((-2) + 2) = f'(0) = -$\dfrac{1}{3}$ s'(-1) = f'((-1) + 2) = f'(1) = -1 s'(0) = f'((0) + 2) = f'(2) = -2 s'(1) = f'((1) + 2) = f'(3) = -4 s'(2) = f'((2) + 2) = f'(4) = Not possible since f'(4) has not been given. s'(3) = f'((3) + 2) = f'(5) = Not possible since f'(5) has not been given.
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