Answer
$g'(x)=2xf'(x^2).$
Work Step by Step
Using the Chain Rule:
$u=x^2$; $\dfrac{du}{dx}=2x$
$\dfrac{d}{du}f(u)=f'(u)=f'(x^2)$
$\dfrac{d}{dx}f(x)=\dfrac{d}{du}f(u)\times\dfrac{du}{dx}=2xf'(x^2).$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 2 - Differentiation - 2.4 Exercises - Page 137: 100
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