Answer
The derivative is $12x^3-12x^2+15$.
Work Step by Step
Product Rule: y'=$((u(x)(v(x))’=u'(x)v(x)+u(x)v’(x))$
$u(x)=(3x-4) ;u’(x)=(3) $
$v(x)=(x^3+5) ;v’(x)=(3x^2) $
$y'=(3)(x^3+5)+(3x-4)(3x^2)=$
$(3x^3+15)+(9x^3-12x^2)=$
$12x^3-12x^2+15$
