Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 2 - Differentiation - 2.3 Exercises - Page 125: 44



Work Step by Step

$y=g(x)+h(x)\rightarrow g(x)=x$ and $h(x)=\cot(x)$. Using the Power Rule: $g'(x)=1$. By Theorem $2.9$: $h'(x)=\frac{d}{dx}(\cot(x))=-\csc^2(x)$. Using the Sum Rule $y'=g'(x)+h'(x)$. $y'=1-\csc^2(x)$.
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