Answer
The limit is
$$\lim_{(x,y)\to(0,2)}\frac{x}{y}=0.$$
The function has a discontinuity on $zx$ plane.
Work Step by Step
This limit is calculated by a simple substitution
$$\lim_{(x,y)\to(0,2)}\frac{x}{y}=\frac{0}{2}=0.$$
This function is continuous whenever $y_0\neq0$ because for every ordered pair $(x_0,y_0)$, $y_0\neq0$ we have
$$\lim_{(x,y)\to(x_0,y_0)}\frac{x}{y}=\frac{x_0}{y_0}.$$
But, when $y_0=0$, this limit is cannot be $x_0/y_0$ because we cannot divide by zero so the function is discontinuous on a plane $y=0$ which is the $zx$ plane.
