Answer
$$4(y^2+z^2)=(4-x^2)$$
Work Step by Step
By the definition of revolution about x-axis,
$$z\rightarrow \sqrt{y^2+z^2}$$
Substituting in $2z=\sqrt{4-x^2}$, we get
$$2\sqrt{y^2+z^2}=\sqrt{4-x^2}$$
$$4(y^2+z^2)=(4-x^2)$$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 11 - Vectors and the Geometry of Space - 11.6 Exercises - Page 803: 34
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