Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.6 Exercises - Page 802: 33

Answer

$$ z=2\sqrt{y^2+x^2}$$

Work Step by Step

By the definition of revolution about z-axis, $$y\rightarrow \sqrt{y^2+x^2}$$ Substituting in $z=2y$, we get $$ z=2\sqrt{y^2+x^2}$$
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