Answer
$(x-1)^2+(y+3)^2+(z+4)^2=25$
Center: $(1,-3,-4)$ Radius: $5$
Work Step by Step
$x^2+y^2+z^2-2x+6y+8z+1=0$
$x^2+y^2+z^2-2x+6y+8z+1=(x-1)^2-1+(y+3)^2-9+(z+4)^2-16+1$
$=(x-1)^2+(y+3)^2+(z+4)^2-25=0$
$(x-1)^2+(y+3)^2+(z+4)^2=25$
Center: $(1,-3,-4)$ Radius: $5$