Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.2 Exercises - Page 763: 40

Answer

$$(x+3)^2+(y-2)^2+(z-4)^2=9$$

Work Step by Step

Center is $(-3,2,4)$ and tangent to $yz$. If it is tangent to the $yz$-plane, then the distance from the surface to the center is just the magnitude of the $x$-coordinate of the center. Therefore, the radius is $3$. So the equation of the sphere is $$(x+3)^2+(y-2)^2+(z-4)^2=9$$
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