Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.1 Exercises - Page 757: 92

Answer

See explanation

Work Step by Step

Examine the attached figure to convince yourself that this is true. Algebraically we can see that if the sides of the triangles are represented by the vectors $\mathbf{a}$, $\mathbf{b}$, and $\mathbf{a-b}$, then the segment going from the midpoint of $\mathbf{a}$ to the midpoint of $\mathbf{b}$ can be represented by the vector $\frac{1}{2}\mathbf{a}-\frac{1}{2}\mathbf{b}$. This vector has the same direction as $\mathbf{a}-\mathbf{b}$ and so they are parallel.
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