Answer
True
Work Step by Step
If $\mathbf{u}$ is a unit vector then $\|\mathbf{u}\|=1$. If $\mathbf{u}=a\mathbf{i}+b\mathbf{j}$ then $\|\mathbf{u}\|=\sqrt{a^2+b^2}$ so
$\sqrt{a^2+b^2}=1$ and therefore $a^2+b^2=1^2=1.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 11 - Vectors and the Geometry of Space - 11.1 Exercises - Page 757: 87
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