Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 11 - Vectors and the Geometry of Space - 11.1 Exercises: 51

Answer

$$\mathbf{v}=\left(-\sqrt{3},1\right)$$

Work Step by Step

$\|\mathbf{v}\|=2\hspace{5mm}\theta=150^\circ$ $\mathbf{v}_x=\|\mathbf{v}\|\cos{\theta}=2\cos{150^\circ}=-2\times\frac{\sqrt{3}}{2}=-\sqrt{3}$ $\mathbf{v}_y=\|\mathbf{v}\|\sin{\theta}=2\sin{150^\circ}=2\times\frac{1}{2}=1$ $$\mathbf{v}=\left(-\sqrt{3},1\right)$$
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