## Calculus 10th Edition

$\|\mathbf{v}\|=(3,0)$
$\|\mathbf{v}\|=3\hspace{5mm}\theta=0^\circ$ An angle of 0 degrees means that there is no $y$-component meaning all of the magnitude is due to the $x$-component. So $\|\mathbf{v}\|=(3,0)$