Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 10 - Conics, Parametric Equations, and Polar Coordinates - Review Exercises - Page 744: 77

Answer

$$y = - \frac{1}{2}{x^2}$$

Work Step by Step

$$\eqalign{ & r = - 2\sec \theta \tan \theta \cr & r = - 2\left( {\frac{1}{{\cos \theta }}} \right)\left( {\frac{{\sin \theta }}{{\cos \theta }}} \right) \cr & {\text{Multiply both sides of the equation by }}\cos \theta \cr & r\cos \theta = - 2\cos \theta \left( {\frac{1}{{\cos \theta }}} \right)\left( {\frac{{\sin \theta }}{{\cos \theta }}} \right) \cr & r\cos \theta = - 2\left( {\frac{{\sin \theta }}{{\cos \theta }}} \right) \cr & {\text{Convert to rectangular form, using }}y = r\sin \theta ,{\text{ }}x = r\cos \theta \cr & x = - 2\left( {\frac{{y/r}}{{x/r}}} \right) \cr & x = - 2\left( {\frac{y}{x}} \right) \cr & - \frac{1}{2}{x^2} = y \cr & {\text{The equation represents a parabola}} \cr & {\text{Graph}} \cr} $$
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