Answer
Rectangular coordinates: $(- \sqrt 3 , 1) \approx (-1.73 , 1)$
Work Step by Step
In polar coordinates, the first number represents the value for $r$, and the second number represents the value for $\theta$.
$(-2, \frac{11\pi} 6)$
Thus: $r = -2$ and $\theta = \frac {11\pi} 6$
Knowing that $x = rcos(\theta)$ and $y = rsin(\theta):$
$x = rcos(\theta) = (-2)(cos(\frac{11\pi} 6)) = (-2)(\frac {\sqrt 3} 2) = -\sqrt 3$
$y = rsin(\theta) = (-2)(sin(\frac{11\pi} 6)) = (-2)(-\frac { 1} 2) = 1$
