Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 10 - Conics, Parametric Equations, and Polar Coordinates - 10.4 Exercises - Page 722: 56

Answer

$d \approx 12.0652$

Work Step by Step

$$\eqalign{ & {\text{Let the points: }}\underbrace {\left( {8,\frac{{7\pi }}{4}} \right)}_{\left( {{r_1},{\theta _1}} \right)}{\text{ and }}\underbrace {\left( {5,\pi } \right)}_{\left( {{r_2},{\theta _2}} \right)} \cr & {\text{Apply }}d = \sqrt {r_1^2 + r_2^2 - 2{r_1}{r_2}\cos \left( {{\theta _1} - {\theta _2}} \right)} \cr & d = \sqrt {{{\left( 8 \right)}^2} + {{\left( 5 \right)}^2} - 2\left( 8 \right)\left( 5 \right)\cos \left( {\frac{{7\pi }}{4} - \pi } \right)} \cr & {\text{Simplifying}} \cr & d = \sqrt {64 + 25 - 80\cos \left( {\frac{{3\pi }}{4}} \right)} \cr & d = \sqrt {89 - 80\left( { - \frac{{\sqrt 2 }}{2}} \right)} \cr & d = \sqrt {89 + 40\sqrt 2 } \cr & d \approx 12.0652 \cr} $$
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