Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 69: 108

Answer

Please see below.

Work Step by Step

We prove the proposition by induction on $n$. Because of Theorem 1.1 part 2. the statement is clearly true for the case $n=1$. Now suppose that the statement is true for $n=k$, that is,$$\lim_{x \to c}x^k=c^k.$$We must show that this is also true for $n=k+1$. We have$$\lim_{x \to c}x^{k+1}=\lim_{x \to c}x^kx=c^kc=c^{k+1},$$where the last equality was obtained from Theorem 1.2 part 3., that is $\lim_{x \to c}[f(x)(g(x)]=[\lim_{x \to c}f(x)][\lim_{x \to c}g(x)]$, Theorem 1.1 part 2., and the induction hypothesis.
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