Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.2 Exercises - Page 55: 4

Answer

$\lim\limits_{x \to 0}\frac{\frac{1}{x+1}-\frac{1}{4}}{x-3} = -0.0625 = -\frac{1}{16} $

Work Step by Step

We can see from the graph below that $\lim\limits_{x \to 0}\frac{\frac{1}{x+1}-\frac{1}{4}}{x-3}$ approaches the value $-0.0625$ which is equivalent to $-\frac{1}{16}$
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