Answer
$\lim\limits_{x \to 3}\frac{x-3}{x^2-9}= \frac{1}{6}$
Work Step by Step
From the graph we see that $\lim\limits_{x \to 3}\frac{x-3}{x^2-9}$ approaches the value $0.1666666$.... which is approximately equal to $\frac{1}{6}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.2 Exercises - Page 55: 2
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
