Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 9 - Infinite Series - 9.6 Alternating Series; Absolute And Conditional Convergence - Exercises Set 9.6 - Page 646: 1

Answer

Convergent

Work Step by Step

Alternating series Test: Let us suppose a series $a_n$ such that $a_n=(-1)^{n+1} b_n$ or $a_n=(-1)^n b_n$ when $b_n \geq 0$ for all $n$. 1) $\lim\limits_{n \to \infty}b_n=0$ 2) $b_n$ shows a decreasing sequence. For a series to be convergent, the above two conditions must be satisfied. We have: $b_k=\dfrac{1}{2k+1}$ 1) We see that $\lim\limits_{k \to \infty}b_k=\lim\limits_{k \to \infty} \dfrac{1}{2k+1}\\=\dfrac{1}{\infty}\\=0$ (2) In $b_k$, the denominator is increasing, so $b_k$ shows a decreasing sequence. We conclude that both conditions of the Alternating series Test are satisfied, so the given series is convergent.
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