Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 6 - Exponential, Logarithmic, And Inverse Trigonometric Functions - Chapter 6 Review Exercises - Page 485: 29

Answer

$$y' = 2x$$

Work Step by Step

$$\eqalign{ & y = {e^{\ln \left( {{x^2} + 1} \right)}} \cr & {\text{use the inverse property }}{e^{\ln f\left( x \right)}} = f\left( x \right) \cr & then \cr & y = {x^2} + 1 \cr & {\text{find the derivative}} \cr & y' = \left( {{x^2} + 1} \right) \cr & y' = 2x \cr} $$
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