Answer
$${f_{avg}} = \frac{1}{{e - 1}}$$
Work Step by Step
$$\eqalign{
& {\text{The average value of the function is:}} \cr
& {f_{avg}} = \frac{1}{{e - 1}}\int_1^e {\frac{1}{x}} dx \cr
& {\text{Integrate and evaluate}} \cr
& {f_{avg}} = \frac{1}{{e - 1}}\left[ {\ln x} \right]_1^e \cr
& {f_{avg}} = \frac{1}{{e - 1}}\left( {\ln e - \ln 1} \right) \cr
& {f_{avg}} = \frac{1}{{e - 1}} \cr} $$