Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 6 - Exponential, Logarithmic, And Inverse Trigonometric Functions - 6.3 Derivatives Of Inverse Functions; Derivatives And Integrals Involving Exponential Functions - Exercises Set 6.3 - Page 432: 23


$f'(x) = (1-3e^{3x})e^{x-e^{3x}}$

Work Step by Step

In order to derivate this function you have to apply the chain rule Let's make a «u» substitution to make it easier $f(u) = e^u$ $u=x-e^{3x}$ Derivate the function: $f'(u) = u'e^u$ Now let's find u' *Note: Here you have to apply the chain rule again $u' = 1 - 3e^{3x}$ Then undo the substitution, simplify and get the answer: $f'(x) = (1-3e^{3x})e^{x-e^{3x}}$
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