## Calculus, 10th Edition (Anton)

$f'(x) = (1-3e^{3x})e^{x-e^{3x}}$
In order to derivate this function you have to apply the chain rule Let's make a «u» substitution to make it easier $f(u) = e^u$ $u=x-e^{3x}$ Derivate the function: $f'(u) = u'e^u$ Now let's find u' *Note: Here you have to apply the chain rule again $u' = 1 - 3e^{3x}$ Then undo the substitution, simplify and get the answer: $f'(x) = (1-3e^{3x})e^{x-e^{3x}}$