Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 6 - Exponential, Logarithmic, And Inverse Trigonometric Functions - 6.2 Derivatives And Integrals Involving Logarithmic Functions - Exercises Set 6.2 - Page 426: 68

Answer

$$\frac{1}{2}\ln 2$$

Work Step by Step

$$\eqalign{ & \int_{1/2}^1 {\frac{1}{{2x}}} dx \cr & {\text{drop out the constant}} \cr & = \frac{1}{2}\int_{1/2}^1 {\frac{1}{x}} dx \cr & {\text{integrate}} \cr & = \frac{1}{2}\left[ {\ln \left| x \right|} \right]_{1/2}^1 \cr & {\text{evaluate}} \cr & = \frac{1}{2}\left[ {\ln \left| 1 \right| - \ln \left| {1/2} \right|} \right] \cr & = \frac{1}{2}\ln 2 \cr} $$
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