Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 6 - Exponential, Logarithmic, And Inverse Trigonometric Functions - 6.2 Derivatives And Integrals Involving Logarithmic Functions - Exercises Set 6.2 - Page 426: 65

Answer

$=t+\ln(t)+C$

Work Step by Step

Splitting apart the numerator into two separate terms leaves $$\int(1+\frac{1}{t})dt$$ Using the power rule for integration leaves $t+ln(t)+C$.
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