Answer
$y' = \dfrac{1}{1+x}$
Work Step by Step
In order to derivate this function you have to apply the chain rule
$f'(x) = \dfrac{u'}{u}$, where $u=1+x$ and $u' = 1$
$y' = \dfrac{1}{1+x}$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 6 - Exponential, Logarithmic, And Inverse Trigonometric Functions - 6.2 Derivatives And Integrals Involving Logarithmic Functions - Exercises Set 6.2 - Page 425: 3
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