Answer
$$\left( {\bf{a}} \right) - 3,\,\,\,\left( {\bf{b}} \right)4,\,\,\,\left( {\bf{c}} \right)3,\,\,\,\left( {\bf{d}} \right)\frac{1}{2}$$
Work Step by Step
$$\eqalign{
& \left( {\bf{a}} \right){\log _{10}}\left( {0.001} \right) \cr
& {\text{write }}0.001{\text{ as }}\frac{1}{{{{10}^3}}} \cr
& = {\log _{10}}\left( {\frac{1}{{{{10}^3}}}} \right) \cr
& {\text{use the exponential property }}\frac{1}{{{a^n}}} = {a^{ - n}} \cr
& = {\log _{10}}\left( {{{10}^{ - 3}}} \right) \cr
& {\text{use the logarithmic property }}\log {a^n} = n\log a \cr
& = - 3{\log _{10}}\left( {10} \right) \cr
& {\text{simplify}} \cr
& = - 3\left( 1 \right) \cr
& = - 3 \cr
& \cr
& \left( {\bf{b}} \right){\log _{10}}\left( {{{10}^4}} \right) \cr
& {\text{use the logarithmic property }}\log {a^n} = n\log a \cr
& = 4{\log _{10}}\left( {10} \right) \cr
& {\text{use the logarithmic property }}{\log _a}a = 1 \cr
& = 4\left( 1 \right) \cr
& = 4 \cr
& \cr
& \left( {\bf{c}} \right)\ln \left( {{e^3}} \right) \cr
& {\text{use the logarithmic property }}\ln {a^n} = n\ln a \cr
& = 3\ln e \cr
& {\text{simplify}} \cr
& = 3\left( 1 \right) \cr
& = 3 \cr
& \cr
& \left( {\bf{d}} \right)\ln \left( {\sqrt e } \right) \cr
& {\text{write }}\sqrt e {\text{ as }}{e^{1/2}} \cr
& = \ln {e^{1/2}} \cr
& {\text{use the logarithmic property }}\ln {a^n} = n\ln a \cr
& = \frac{1}{2}\ln e \cr
& {\text{simplify}} \cr
& = \frac{1}{2}\left( 1 \right) \cr
& = \frac{1}{2} \cr} $$