Answer
$$\left( {\bf{a}} \right)4,\,\,\,\left( {\bf{b}} \right) - 5,\,\,\,\left( {\bf{c}} \right)1,\,\,\,\left( {\bf{d}} \right)\frac{1}{2}$$
Work Step by Step
$$\eqalign{
& \left( {\bf{a}} \right){\log _2}16 \cr
& {\text{write 16 as }}{{\text{2}}^4} \cr
& = {\log _2}{2^4} \cr
& {\text{use the logarithmic property }}\log {a^n} = n\log a \cr
& = 4{\log _2}2 \cr
& {\text{simplify}} \cr
& = 4\left( 1 \right) \cr
& = 4 \cr
& \cr
& \left( {\bf{b}} \right){\log _2}\left( {\frac{1}{{32}}} \right) \cr
& {\text{write 32 as }}{{\text{2}}^5} \cr
& = {\log _2}\left( {\frac{1}{{{2^5}}}} \right) \cr
& {\text{use the exponential property }}\frac{1}{{{a^n}}} = {a^{ - n}} \cr
& = {\log _2}{2^{ - 5}} \cr
& {\text{use the logarithmic property }}\log {a^n} = n\log a \cr
& = - 5{\log _2}2 \cr
& {\text{simplify}} \cr
& = - 5\left( 1 \right) \cr
& = - 5 \cr
& \cr
& \left( {\bf{c}} \right){\log _4}4 \cr
& {\text{use the logarithmic property }}{\log _a}a = 1 \cr
& {\log _4}4 = 1 \cr
& \cr
& \left( {\bf{d}} \right){\log _9}3 \cr
& {\text{write 3 as }}{{\text{9}}^{1/2}} \cr
& = {\log _9}{9^{1/2}} \cr
& {\text{use the logarithmic property }}\log {a^n} = n\log a \cr
& = \frac{1}{2}{\log _9}9 \cr
& {\text{simplify}} \cr
& = \frac{1}{2}\left( 1 \right) \cr
& = \frac{1}{2} \cr} $$