Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 5 - Applications Of The Definite Integral In Geometry, Science, And Engineering - 5.1 Area Between Two Curves - Exercises Set 5.1 - Page 353: 26

Answer

$$A \approx 18.759122$$

Work Step by Step

$$\eqalign{ & {\text{using a CAS we found that the intersection points between}} \cr & {\text{the curves are at }}x = 0,{\text{ }}x \approx - 1.1080{\text{ and }}x \approx 2.5669 \cr & {\text{From the graph we can see that the area is given by:}} \cr & A = \int_{ - 1.1080}^0 {\left( {{x^5} - 2{x^4} - 3x - {x^3}} \right)} dx + \int_0^{2.5669} {\left( {{x^3} - {x^5} + 2{x^4} + 3x} \right)dx} \cr & {\text{Integrating by using a CAS, we obtain}} \cr & A \approx 1.121932 + 17.63719 \cr & A \approx 18.759122 \cr} $$
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