Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - Chapter 4 Review Exercises - Page 343: 22

Answer

\begin{align} \int_0^1 |2x-1| \ dx = \frac{1}{2} \end{align}

Work Step by Step

$\text{The given definite integral is}$ \begin{align} \int_0^1 |2x-1| \ dx \end{align} $\text{The alternative way to calculate the integral is to find the area under}$ $\text{the function. The given modulus function forms 2 right triangles. The}$ $\text{area of each triangle is:}$ \begin{align} A = \frac{1}{2} \times 1 \times \frac{1}{2} = \frac{1}{4} \end{align} $\text{Thus, the total area and consequently, the value of the definite integral:}$ \begin{align} \int_0^1 |2x-1| \ dx = 2 \times A = \frac{1}{2} \end{align}
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