Answer
See explanation.
Work Step by Step
Left side equation
\[
\int_{0}^{t} (-x+t)f g(x) d x
\]
\[
-\int_{t}^{0} f(u) (-u+t)g d u
\]
Substitution $-x+t=u$
Replace $(d u)\ with\ (-d x)$
\[
\int_{0}^{t} f(u) g(t-u) d u
\]
Rewrite integral
\[
\int_{0}^{t} f(x) (-x+t) g d u
\]