Answer
-1
Work Step by Step
$\int^{2}_{-1}[f(x)+2g(x)]dx$
$=\int^{2}_{-1}f(x)dx+2\int^{2}_{-1}g(x)dx$
$=5+(2\times-3)$=5-6= -1
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 4 - Integration - 4.5 The Definite Integral - Exercises Set 4.5 - Page 308: 21
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