Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.5 The Definite Integral - Exercises Set 4.5 - Page 308: 21



Work Step by Step

$\int^{2}_{-1}[f(x)+2g(x)]dx$ $=\int^{2}_{-1}f(x)dx+2\int^{2}_{-1}g(x)dx$ $=5+(2\times-3)$=5-6= -1
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