Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.8 Related Rates - Exercises Set 2.8 - Page 173: 6

Answer

(b)$A=\pi r^2$ (c)$\frac{dA}{dt}=2 \pi r\frac{dr}{dt}$ (d) $\frac{dA}{dt}=20 \pi \frac{cm^2} {dt}$

Work Step by Step

(b) $A=\pi r^2$ (c)$ \frac{dA}{dr}=\frac{dA}{dt} \frac{dt}{dr}$ Putting $A=\pi r^2 $ in the RHS $ \frac {d (\pi r^2)} {dr}= \frac{dA}{dt} \frac{dt}{dr} $ $ \pi \frac {d (r^2)} {dr}= \frac{dA}{dt} \frac{dt}{dr} $ $ \pi (2r) = \frac{dA}{dt} \frac{dt}{dr} $ $ \frac{dA}{dt} \frac{dt}{dr} =2\pi r$ $\frac{dA}{dt}=\frac {2 \pi r} {\frac{dt}{dr}} =2\pi r \frac{dr}{dt}$ $\frac{dA}{dt}=2\pi r \frac{dr}{dt}$ ................ eq (1) (d) Putting $ r=5cm$ and $ \frac{dr}{dt}= 2 cm/s$ in equation (1) $\frac{dA}{dt}=2\pi \times 5\times 2=20 \pi \frac{cm^2} {s}$
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