Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.8 Related Rates - Exercises Set 2.8 - Page 173: 12

Answer

$180 \pi $ $ft^2/s$

Work Step by Step

Let Area =A Radius=r Then $A=\pi r^2$ Taking derivative with respect to t $\frac{dA}{dt}=\frac{d(\pi r^2)}{dt}=\frac{d(\pi r^2)}{dr} \frac{dr}{dt}=\pi \frac{d(r^2)}{dr} \frac{dr}{dt}=2\pi r \frac{dr}{dt}$ ................ eq(1) Now according to the given condition $r=\frac{dr}{dt}\times t$ .................... eq (2) Put $t=10$sec, $\frac{dr}{dt}=3 $ft/sec in equation (2) $\Longrightarrow$ $r=3\times10=30 ft$ Putting $r=30 $ft, $\frac{dr}{dt}=3 $ft/sec in equation (1) $\frac{dA}{dt}=2\pi \times 30 \times 3=180 \pi$ $ft^2/s$
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