Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.7 Implicit Differentiation - Exercises Set 2.7 - Page 166: 31


$\dfrac{da}{dt} = \dfrac{4t^3-6a^2}{4a^3-12at}$

Work Step by Step

In order to derivate this function you have to apply implicit differentation method. Then derivate the whole equation. Rember the put a' every time you derivate a $4a^3a'-4t^3-12aa't+6a^2=0$ Solve for a' and you have the answer $a'(4a^3-12at)=4t^3-6a^2$ $a' = \dfrac{4t^3-6a^2}{4a^3-12at}$
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