Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.6 The Chain Rule - Exercises Set 2.6 - Page 159: 66

Answer

$A=-\frac{4}{7}$

Work Step by Step

We begin by solving for the derivatives of $y$: $y = Asin(3t)$ $\frac{dy}{dt} = Acos(3t) * (\frac{d}{dt} 3t) = 3Acos(3t)$ $\frac{d^2y}{dt^2} = -3Asin(3t) * (\frac{d}{dt}3t)=-9Asin(3t)$ We substitute these values into the equation and solve for $A$: $\frac{d^2y}{dt^2} + 2y = 4sin(3t)$ $-9Asin(3t) + 2(Asin(3t) =4sin(3t)$ $-7Asin(3t) = 4sin(3t)$ $-7A = 4$ $A=-\frac{4}{7}$
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