Answer
True
Work Step by Step
We apply the chain rule repeatedly:
$y = sin^3(3x^3)$
$\frac{dy}{dx} = 3sin^2(3x^3)*(\frac{dy}{dx} sin^3(3x^3))$
$\frac{dy}{dx} = 3sin^2(3x^3)*cos(3x^3) * (\frac{dy}{dx}3x^3)$
$\frac{dy}{dx} = 3sin^2(3x^3)*cos(3x^3)*9x^2$
$\frac{dy}{dx} = 27x^2sin^2(3x^3)*cos(3x^3)$
which matches the expression in the question.
