Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 2 - The Derivative - 2.6 The Chain Rule - Exercises Set 2.6: 2

Answer

$(f\circ{g})'(2)=-15$

Work Step by Step

$(f\circ{g})(x)=f(g(x))$ $\frac{d}{dx}(f(g(x))=f'(g(x))\times{g'(x)}$ $(f\circ{g})'(2)=f'(g(2))\times{g'(2)}$ $(f\circ{g})'(2)=f'(9)\times{-3}$ $(f\circ{g})'(2)=5\times{-3}$ $(f\circ{g})'(2)=-15$
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