Answer
$(f\circ{g})'(0)=6$
Work Step by Step
$(f\circ{g})(x)=f(g(x))$
$\frac{d}{dx}(f(g(x))=f'(g(x))\times{g'(x)}$
$(f\circ{g})'(0)=f'(g(0))\times{g'(0)}$
$(f\circ{g})'(0)=f'(0)\times{3}$
$(f\circ{g})'(0)=2\times{3}$
$(f\circ{g})'(0)=6$
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 2 - The Derivative - 2.6 The Chain Rule - Exercises Set 2.6 - Page 157: 1
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