Answer
See explanation
Work Step by Step
1. \(\nabla \cdot (\mathbf{k} \mathbf{A}) = k \nabla \cdot \mathbf{A}\)
2. \(\nabla \cdot (\mathbf{A} + \mathbf{B}) = \nabla \cdot \mathbf{A} + \nabla \cdot \mathbf{B}\)
3. \(\nabla \cdot (\phi \mathbf{F}) = \phi \nabla \cdot \mathbf{F} + \nabla \phi \cdot \mathbf{F}\)
4. \(\nabla \cdot (\nabla \times \mathbf{F}) = 0\)