Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 13 - Partial Derivatives - 13.1 Functions Of Two Or More Variables - Exercises Set 13.1 - Page 916: 55

Answer

See the explanation

Work Step by Step

for k=-2,-1,1,2 you will get hyperbolas for k=0 intersecting lines Given z= x^2-y^2 z=k=-2,-1,0,1,2 for k=-2 x^2-y^2 = -2 =>(x^2/-2 )-(y^2/-2)=1 for k=-1 x^2-y^2 = -1 =>(x^2/-1)-(y^2/-1)=1 for k=0 x^2-y^2 = 0 for k=-2 x^2-y^2 = 1 for k=-2 x^2-y^2 = 2 =>(x^2/2 )-(y^2/2)=1
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