Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 13 - Partial Derivatives - 13.1 Functions Of Two Or More Variables - Exercises Set 13.1 - Page 916: 53

Answer

See explanation

Work Step by Step

Given, z=x^2+y & k=−2,−1,0,1,2 for k=-2,-1,0,1,2 you will get parabola Let, z=k=-2,-1,0,1,2 for k=-2 x^2+y=-2 =>x^2=-y-2 [parabola opens down vertex (0,-2)] for k=-1 x^2+y=-1 =>x^2=-y-1 [parabola opens down vertex (0,-1)] for k=0 x^2+y=0 =>x^2=-y [parabola opens down vertex (0,0)] for k=1 x^2+y=1 =>x^2=-y+1 [parabola opens down vertex (0,1)] for k=2 x^2+y=2 =>x^2=-y+2 [parabola opens down vertex (0,2)]
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