Answer
Refer to the sketch in the picture
Work Step by Step
$f(x, y) = \sqrt (x^2+y^2-4)$
First in order to sketch the domain of this function, we need to find it from the function
$x^2+y^2-4\geq 0$
$x^2+y^2\geq 4$
Domain { x,y are members of Real numbers and $x^2+y^2\geq 4$}
The graph is a circle of radius $r = 2$
