Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 12 - Vector-Valued Functions - 12.6 Motion Along A Curve - Exercises Set 12.6 - Page 893: 46

Answer

$ \|\mathbf{a}_N\| = 6\sqrt{2}$

Work Step by Step

Step 1 Given: \[ \|\mathbf{a}(1)\| = 9 \] \[ \|\mathbf{a}(1)\| = 9; \quad \mathbf{a}_T(1)\mathbf{T}(1) = 2\mathbf{i} - 2\mathbf{j} + \mathbf{k} \] Step 2 Since: \[ \mathbf{a} = \mathbf{a}_T\mathbf{T} + \mathbf{a}_N\mathbf{N} \] Then: \[ \|\mathbf{a}\|^2 = \|\mathbf{a}_T\|^2 + \|\mathbf{a}_N\|^2 = 9 + \|\mathbf{a}_N\|^2 \] \[ 81 = 9 + \|\mathbf{a}_N\|^2 \] Hence: \[ \|\mathbf{a}_N\| = \sqrt{72}. \] Result \[ \|\mathbf{a}_N\| = 6\sqrt{2} \]
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