Answer
$$ x=1-2y^2 $$
This shows an equation for a parabola.
Work Step by Step
We have: $x= \cos 2 t$ and $y=\sin t$
Now, use the identity $$\cos 2t=1-2 sin^2 t \\ x=1-2(y)^2\\ x=1-2y^2 $$
This shows an equation for a parabola.
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 10 - Parametric And Polar Curves; Conic Sections - 10.1 Parametric Equations; Tangent Lines And Arc Length For Parametric Curves - Exercises Set 10.1 - Page 701: 9
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