Answer
$$y=x-1$$ $$ \text{ Straight Line }$$
Work Step by Step
We have: $x=\sec^2t$ and $y= \tan^2t$
Now, use the identity $$\sec^2 t-\tan^2 t=x-y \\ 1=x-y \\y=x-1$$
This shows a straight line.
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 10 - Parametric And Polar Curves; Conic Sections - 10.1 Parametric Equations; Tangent Lines And Arc Length For Parametric Curves - Exercises Set 10.1 - Page 701: 12
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