Calculus, 10th Edition (Anton)

by Anton, Howard

Published by Wiley

ISBN 10: 0-47064-772-8

ISBN 13: 978-0-47064-772-1

Chapter 10 - Parametric And Polar Curves; Conic Sections - 10.1 Parametric Equations; Tangent Lines And Arc Length For Parametric Curves - Exercises Set 10.1 - Page 701: 10

Answer

$$ y =(x-3)^2-9$$ $$ \text{ Parabola }$$

Work Step by Step

We have: $x=4t+3 \implies t=\dfrac{x-3}{4}$ and $y=16 t^2-9$ Now, $$y=16t^2-4 \\y=16 (\dfrac{x-3}{4})^2-9 \\ y =(x-3)^2-9$$ This shows an equation for a parabola.

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